A obtained by Ostwald's method involving air | vedclass

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(C) In the Ostwald's process,$NH_3$ is oxidized to $NO$ $(A)$: $4 NH_3 + 5 O_2 \xrightarrow{Pt/Rh} 4 NO + 6 H_2O$.$NO$ $(A)$ on further oxidation with

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$NO, NO_2$

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(C) In the Ostwald's process,$NH_3$ is oxidized to $NO$ $(A)$: $4 NH_3 + 5 O_2 \xrightarrow{Pt/Rh} 4 NO + 6 H_2O$.$NO$ $(A)$ on further oxidation with air produces $NO_2$ $(B)$: $2 NO + O_2 \longrightarrow 2 NO_2$.$NO_2$ $(B)$ on hydration (reaction with water) forms nitric acid $(HNO_3)$ and releases $NO$ $(A)$: $3 NO_2 + H_2O \longrightarrow 2 HNO_3 + NO$.Nitric acid $(HNO_3)$ is an oxoacid of Nitrogen that gives a positive brown ring test and can produce $NO$ upon reduction.

$A$ obtained by Ostwald's method involving air oxidation of $NH_3$,upon further air oxidation produces $B$. $B$ on hydration forms an oxoacid of Nitrogen along with evolution of $A$. The oxoacid also produces $A$ and gives positive brown ring test.

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